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| # 用3*1d list去翻轉會不會很耗時間
# 或是可以考慮使用兩個1d list 去紀錄idx
# [上*4個] [旁邊的數字] [下面*4]
# 每次移動就改idx值(跑中間list)
# 前到下 後到上 上到前 下到後 也可以不用?
from sys import stdin
def up(a):
global idx, mid, back, front
old_back = back[a][0]
old_front = front[a][0]
front[a] = [mid[a][idx[a]] for i in range(4)]
if idx[a] + 2 >3:
if idx[a] == 2:
back[a] = [mid[a][0] for i in range(4)]
mid[a][0] = old_front
if idx[a] == 3:
back[a] = [mid[a][1] for i in range(4)]
mid[a][1] = old_front
else:
back[a] = [mid[a][idx[a]+2] for i in range(4) ]
mid[a][idx[a] + 2] = old_front
mid[a][idx[a]] = old_back
# old_front到對面
def right(a):
global idx
if idx[a] - 1 < 0:
idx[a] = 3
else:
idx[a] -= 1
#n, m = 1, 2
#inp = [[1, -2], [1, -1]]
#back = [3, 3, 3, 3]
#mid = [1, 2, 6, 5]
#front = [4, 4, 4, 4]
#idx = 0 #跑在mid
#right()
#print(back)
#print(mid)
#print(front)
#print(idx)
#up()
n, m = map(int, stdin.readline().split())
idx = [0 for i in range(n)]
back = [[3, 3, 3, 3] for i in range(n)]
mid = [[1, 2, 6, 5] for i in range(n)]
front = [[4, 4, 4, 4] for i in range(n)]
for i in range(m):
a, b = map(int, stdin.readline().split())
if b == -1:
up(a - 1)
elif b == -2:
right(a - 1)
else:
#print(mid[2][idx[2]])
a -= 1
b -= 1
idx[a], idx[b] = idx[b], idx[a]
back[a], back[b] = back[b], back[a]
mid[a], mid[b] = mid[b], mid[a]
front[a], front[b] = front[b], front[a]
#k = 0
for i in range(len(idx)):
if i == 0:
print(mid[i][idx[i]], end = "")
else:
print(f" {mid[i][idx[i]]}", end = "")
|
